Table 'Address'. aren't there anyway i can make it distinct for PokemonIds ? –MonsterMMORPG Dec 8 '12 at 22:02 what would by your expected output? –bummi Dec 8 '12 at 23:02 The issue is this: in our sample data, there are no real duplicates (date+time). Know what you are doing, that it works, and why it works. http://stackoverflow.com/questions/9572131/select-distinct-not-working-as-expected
I'm planning on using: nvarchar ;) –user3352567 May 25 '14 at 1:44 that would probably work too. That syntax is accepted because (employeeID) is just an expression, a reference to a column, which happens to be surrounded by parenthesis. For example, you could write: select distinct (employeeID), (salary) Several functions may not work.
DISTINCT is not a function ... ... Become a paid author More SQL Server Solutions Post a comment or let the author know this tip helped. Notes: a related table is usually referred to as child table. Distinct Not Working C# Register now!
more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Sql Distinct Not Working With Join facebook google twitter rss Free Web Developer Tools Advanced Search Forum Databases MS SQL Development Select Distinct Not Working Thread: Select Distinct Not Working Page 1 of 2 12 Find a limit without l'Hospital. http://stackoverflow.com/questions/23851157/sql-distinct-not-working if all "duplicates" have the same value, is there another column to discriminate them, so we can decide on which one to take?
The first query we run is using case sensitive, so all four rows should show up. Reply roopeshreddy Star 14065 Points 3271 Posts Re: Distinct keyword not working in sql server Jul 06, 2012 05:58 AM|roopeshreddy|LINK Hi, I suspect the syntax -http://blog.sqlauthority.com/2007/12/20/sql-server-distinct-keyword-usage-and-common-discussion/ Hope it helps u... Select Distinct Not Working With Join Should I report it? Select Distinct Not Working Access Subscribe Archives May, 2012 (1) August, 2010 (1) October, 2009 (1) December, 2008 (1) October, 2008 (2) August, 2008 (3) July, 2008 (3) June, 2008 (3) May, 2008 (4) April, 2008
Passing an Array or Table Parameter to a Stored Procedure SELECT * FROM TABLE -- except for these columns In SQL, it's a Case Expression, *not* a Case Statement Returning Random weblink select **distinct** SName as Student, major from Student, Apply where Student.sID = Apply.sID; sql distinct share|improve this question edited May 25 '14 at 1:34 asked May 25 '14 at 1:17 user3352567 Tables and Data We usually have 2 tables in the scenario: one master/parent table, one dependant table, linked through a 1:n relationship, with information such as history, traffic, accounting, etc information. Scan count 0, logical reads 0, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. Distinct Not Working Oracle
asked 2 years ago viewed 3654 times active 2 years ago Upcoming Events 2016 Community Moderator Election ends in 9 days Linked 20 Is there any way to DISTINCT or group Code: SELECT UsersTable.UserID, UsersTable.FirstName, UsersTable.LastName MIN(OrdersTable.OrderID) from UsersTable INNER JOIN OrdersTable on OrdersTable.UserID = UsersTable.UserID GROUP BY OrdersTable.OrderID, UsersTable.UserID, UsersTable.FirstName, UsersTable.LastName Hello Vomster, this code is throwing an error "Incorrect syntax Faq Reply With Quote April 19th, 2011,10:19 PM #11 r937 View Profile View Forum Posts Visit Homepage SQL Consultant Devshed Supreme Being (6500+ posts) navigate here select distinct (item) COLLATE sql_latin1_general_cp1_ci_aiFROM (select 'abcd' itemunion all select 'ABCD'union all select 'defg'union all select 'deFg') items Next Steps You can see how the behavior of the database can impact
Actually the number of rows i get are huge.Is there a way to check if i am getting unique values? –sriram Mar 5 '12 at 18:55 1 Don't trust the Select Distinct Only One Column which is going to take distinc of all fields hope this helps... Pictures Contribute Events User Groups Author of the Year More Info Join About Copyright Privacy Disclaimer Feedback Advertise Copyright (c) 2006-2016 Edgewood Solutions, LLC All rights reserved Some names and products
Table 'Address'. Unless you expect something else of what is a duplicate (and what not) than SQL does actually do. For Smith and Brown, we can forecast no major problems, but Bond lists 2 records for the last day... his comment is here Do it this way : select distinct top 36 tblFoundPokemonsOnRoutes.pokemonId,MonsterTotalStats, MAX(maxLevel) as maxLevel, Case Class WHEN 'Ancient' Then '9' WHEN 'Legendary' Then '8' WHEN 'Zenith' Then '7' WHEN 'Emissary' Then '6'
Not the answer you're looking for? I also tried doing a count (transactionnumber)<2 but could not figure out how to add a where for the item number.So an order for just this itemselect distinct(transactionnumber) from Orders (I I don't see any duplicated rows ... Code: SELECT UsersTable.UserID, UsersTable.FirstName, UsersTable.LastName , MIN(OrdersTable.OrderID) from UsersTable INNER JOIN OrdersTable on OrdersTable.UserID = UsersTable.UserID GROUP BY OrdersTable.OrderID, UsersTable.UserID, UsersTable.FirstName, UsersTable.LastName Sorry, but it is still showing duplicate records, i.e.
What is the meaning of "cow in the middle"? Yes No Do you like the page design? It returns the set of distinct rows over the superset returned by the query, rather than distinct values in a single column. Well, if any of the rows in your result set weren't unique, then SELECT studentid , collegeid , COUNT(*) FROM ( SELECT DISTINCT studentId, CollegeID FROM STUDENT_GROUP ) GROUP BY studentid
Analytical functions: http://www.experts-exchange.com/articles/Database/Miscellaneous/Analytical-SQL-Where-do-you-rank.html DISTINCTROW <> DISTINCT MS Access : http://office.microsoft.com/en-us/access/HP010322051033.aspx UNION vs. Cheers! Why were pre-election polls and forecast models so wrong about Donald Trump? the first one, thank you for your assistance.
This might be fine...